labview, How do I convert 16 bit Binary to ASCII text

I have a 16 bit Binary data string (i.e. 0110000110111000) I need to convert to ascii text using the following format.
 
Note: Name represented by char code set defined in ANSI X3.4 (Std 7-bit ASCII the first bit of each character field will be set to logic zero and the 7-bit ascii code will occupy the remaining 7 bits of the field)
 
Field name             BIT NO            Description
Reserved                   -00- 0           *Note
Character 1                -01-A           MSB
                                   -02-A etc.....
..................................-07-A           LSB
Reserved                   -08-A           *Note
Character 2                -09-A           MSB
                                   -10-A etc .....
..................................-15-A           LSB
 
Is there a simple method I'm missing?
 
 
 

I noticed that the second substring's first character is not a zero as stated in your definition.


The way I interpreted the problem is that the code should zero out the first bit. You can do that by ANDing it with an appropriate integer. The code in the attached image shows one possibility. There are many ways to do this.
<img src=" http://forums.ni.com/attachments/ni/170/191007/1/binaryscan.png "> Message Edited by altenbach on 06-20-2006 01:57 PM


binaryscan.png:
http://forums.ni.com/attachments/ni/170/191007/1/binaryscan.png

I have a 16 bit Binary data string (i.e. 0110000110111000) I need to convert to ascii text using the following format.


Of course we need to know exactly how your "16 bit binary" data string actually looks like. Your question is a bit ambiguous.

- Is it a formatted ASCII string of length 16bytes, containing the letteres 1 and 0?

- Is it a 2byte long raw ASCII string, representing the two bytes?

- ...?

So far, we have assumed case (1). Case (2) would be trivial. ;)

Thank you both for your (Quick!) assistance with providing a solution to the problem.
The data is presented in Hex string format of a 16 bit word. 8 words (16 ASCII Characters) comprise the Target Name in the data. Sometimes the data transmission can get corrupted providing an invalid word which was the case with my original submit. (might have just been a fat finger on the kb)
Here are 8 words that comprise the following message   KNID/T192023
19278, 18756, 12116, 12601, 12848, 12851, 8224, 8224
 
 
 
 
 

Here are 8 words that comprise the following message   KNID/T192023
19278, 18756, 12116, 12601, 12848, 12851, 8224, 8224



Your 8 words should give 16 characters.  The last four must be spaces because there are only 12 characters in KNID/T192023.  Also you stated that the data is in hex, but your 8 words are obviously in decimal.  Anyway, here is a vi to decipher the words.
Once again Altenbach has to come up with a simpler way to do things.  Maybe I should send him all my work for reveiw. :smileywink:Message Edited by tbob on 06-20-2006 04:16 PM


DecimalStringsToAsciiChars.vi:
http://forums.ni.com/attachments/ni/170/191024/1/DecimalStringsToAsciiChars.vi

OK,
tbob and altenbach - You guys make this stuff seem too easy.
Let me pose a new problem - I've already devised a solution but I'd like to see how either of you would approach the problem.
The simplest solution wins a prize! I'll send Two Product Patches to the solution that I like the best. Good Luck!
This is a signed 2's comp problem to describe position (North is positive and south is negative). Input is 2 word hex decimal string array.
The bits are laid out with MSB at the left.
MSB = 2^-1, LSB = 2^-31, Max/Min Value is +/- 5.0000E-01, Resolution 4.6566E-10
2 word message
Field name   BIT NO
MSW       -00- S      Sign
                -01- N      MSB
                -02- N .......-15-N
LSW        -00-N .......-14-N
                -15-N       LSB 

Hmm, so what needs to be done???
So far we know how the data is represented. What kind of input do you have and what kind of output do you want?
(Better just give us an example VI with typical data as default in a control of the desired type and a description on how the output should look like).

I don't know?
What would your solution be for
word 1 = 624
word 2 = 2448
Max/Min Value +/- 1.0240E+03
resolution 3.8147E-06
MSB = 2^12
LSB = 2^-18
Full scale of the data 8.1920E+03

Your problem is way overdetermined, the only thing you need is log2(MSB) (-18 in this case), which gives the resolution.
 
(I don't know why you need the "min/max" and "full scale" and all that. Do you need some additional scaling?)
 
Anyway, the attached (LabVIEW 7.1) is one possibility. You should really check it with some inputs that yield a negative number, though.
 
 
My result for your sample inputs (624,2448) is about 156.Message Edited by altenbach on 06-21-2006 02:02 PM


16bitWordsToScaledDBL.png:
http://forums.ni.com/attachments/ni/170/191298/3/16bitWordsToScaledDBL.png


16bitWordsToScaledDBL.vi:
http://forums.ni.com/attachments/ni/170/191298/4/16bitWordsToScaledDBL.vi

.. log2(MSB) (-18 in this case)...

Log2(LSB) of course. Sorry for the typo. ;)

Altenbach - You are five stars in my book.
I came accross a new problem that I was wondering if you could assist to simplify?
Same type data 16 bit word
Field name    Bit No   Description
Integer             -00- S     Sign Bit
                        -01- N     MSB
                        -02- ..... -10- N
                        -11- N   LSB
Exponent         -12- E   MSB
                         -13-....-14-
                         -15- E   LSB
Integer    Resolution 1    MSB 2^10    LSB 2^0
Exponent  Resolution 1  MSB 2^3      LSB 2^0
Is there a simple way of handling this problem?  
 

Since the LSB of the mantissa is 1 and the exponent is always positive, the result is always an integer and will fit into an I32.
 
I also assume that the exponent is meant to be base 2, i.e. the desired result is (mantissa x 2^exponent). If the definition is different, modify accordingly.
 
Here is a simple possibility to convert to I32 according to the given rules, see if it gives the right answer for you. Sorry, I cannot test this. No guarantee that its right. ;)
 
<img src=" http://forums.ni.com/attachments/ni/170/191628/1/16bitWordToI32.png ">
 
 
 
 Message Edited by altenbach on 06-22-2006 03:52 PM


16bitWordToI32.png:
http://forums.ni.com/attachments/ni/170/191628/1/16bitWordToI32.png


16bitWordToI32.vi:
http://forums.ni.com/attachments/ni/170/191628/2/16bitWordToI32.vi

Here are the details I have for this problem
The value of this data word represented by this format is given by: (Integer) X (16**Exponent)
Exponent is 2's comp with Max and Min Values of 15 and 0 respectively.
The full scale of this data word is 2.36E+21 with Max and Min values for the integer of 2047 and -2048 repectively.
2047*16^15 = 2.36E+21
Thank you again for showing me the direct route rather than working on the bit level.