mfc, Dynamic context CMenu...

microsoft.public.vc.mfc - Microsoft Visual C


mfc >> Dynamic context CMenu...

by Tom » Tue, 25 Nov 2003 18:12:39 GMT

Hi,
As usual I can write:
menu.LoadMenu(IDR_MENU1);
CMenu *pPopup = menu.GetSubMenu( 0 );
pPopup->TrackPopupMenu( TPM_LEFTALIGN | TPM_RIGHTBUTTON, point.x, point.y,
this );
to show a context menu.

But I do not want that since I plan to use the same menu in different
contexts, showing different menu items. And I do not want to delete existing
menu items. I'd much rather add menu items actively!

So, I'd like to create a context menu dynamically, something like:
void CDynMenuView::OnContextMenu(CWnd* pWnd, CPoint point)
{
CMenu menu;
if (!menu.CreatePopupMenu())
return;

menu.InsertMenu(-1,MF_BYCOMMAND|MF_BYPOSITION,ID_POPUP_TEST);

menu.TrackPopupMenu( TPM_LEFTALIGN | TPM_RIGHTBUTTON, point.x, point.y,
this );
}

However, this does not work...
I guess I use ID_POPUP_TEST incorrectly. I want to use ID_POPUP_TEST as a
commandid and menutext, hence defined it as:
IDR_MENU1 MENU DISCARDABLE
BEGIN
POPUP ""
BEGIN
MENUITEM "Test...", ID_POPUP_TEST
END
END

What is the correct way of creating this context menu dynamically?

/Tom



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mfc >> Dynamic context CMenu...

by Doug Harrison [MVP] » Wed, 26 Nov 2003 10:37:54 GMT






Two things:

1. MF_BYCOMMAND and MF_BYPOSITION are mutually exclusive. Use one or the
other but not both. (Actually, if you grep the Windows headers, you'll find
MF_BYCOMMAND is equal to 0, so you end up getting MF_BYPOSITION above.)

2. You forgot to specify the menu item text, which is the 4th and last
parameter. You should create a string resource and load it into a CString,
which you pass to InsertMenu.


That defines a whole new menu resource. You can certainly do that to provide
a standard set of commands for a menu you later modify, but you can also
build a menu from scratch using InsertMenu and related functions.

--
Doug Harrison
Microsoft MVP - Visual C++


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